Target Karate Tae

Target Karate Tae
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Target Karate Tae
Karate Physics Question?

In tae-kwon-do, a hand is slammed down onto a target at a speed of 14 m/s and comes to a stop during the 6.0 ms collision. Assume that during the impact the hand is independent of the arm and has a mass of 0.60 kg. What are the magnitudes of the (a) impulse and (b) average force on the hand from the target?

mass(hand) = 0.60 kg
vf = 14 m/s
vi = 0 m/s
t = 6 ms

a. j = ?
j = pf - pi = mvf - mvi = m(vf-vi)

x component:
jx = m(vfx - vix)
=0.6[(0m/s*scos0)- (14m/s*sin90)]
= -8.40 kgm/s

y component:
jy = m(vfy-viy)
= 0.6[(0m/s*sin0)-(14m/s*cos90)]
=0kgm/s

J = -8.4 i + 0 j

J = sqrt(-8.40^2+0^2)
= *** 8.4kg m/s ***

b. force avg = J/delta t
=8.4 kgm/s / (0.006 sec) = 1400 N

Brandon Searight TKD Focus Target Drills




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